# A particle is moving along a circular path with a constant speed 10ms−1.What is the magnitude of the change in velocity of the particle ,when it moves through an angle of 60∘ around the center of the circle ?

Zero

10m/s

10√2m/s

10√3m/s

## The correct Answer is:B

## ∣∣Δ→V∣∣=2vsinθ2=2vsin30∘=2×10×12=10m/s

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